Particles Physics Experiments
Beam
Target
Detector
To explore sub-atomic structures accelerators are microscopes to see sub-atomic structures.
Particles (p,e) gain lots of momentum by speeding them up to ~ c (speed of ligh), then particle wavelength is very short:
Probug particles shooting high energy particles at a fixed target or to each other provides collisions.
BEAM
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TARGET DETECTOR
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BEAM
DETECTOR
THE OBSERVATION OF PARTICLES ON EMILSION PLATE
Pion which has a high energy and high velocity spreads after hit to a nükleus in the
film and it is spreaded in a three dimentional position.
However a pion particle which has less energy and velocity goes on to lose its energy and after that it becomes spoiled. After this it throws a neutrino particle and at the result of this a muon which has a higher energy found out.
Muon loses it velocity and energy and than it throws a neutrino. At the result of this an
electron exists
Muon and neutrino go on to their direction in opposite ways. However neutrino has not got any heap and iyonize value so it can not be seen with eyes. The energy of neutrino can be calculate with using the energy and momentum of pion and muon.
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(300 micron silver bromide film)
TO CALCULATE THE MOMENTUM OF MUON
The becoming spoiled and effects of the reaction of pion which is in silver bromude film can be seen with a research with stereo optic microscope.
With using the layer and horizontal values of microscope, the length of muon which is in the film can be calculate as micron value.
We take the value of momentum which is opposite to lenght in lenght-momentum graphic.
Momentum (MeV/c)
2,95
2,9
2,85
2,8
2,75
2,7
2,65
2,6
2,55
2,5 lenght(micron)
400 421 441 450 490 529 539 548 568
TO CALCULATE THE ENERGY OF NEURINO
E2 = p 2 . c 2 + m 2 .c4
E = Energy
P = Momentum
M= Heap
C= light’s speed
MUON
E2 = 2,92 MeV/c . c2 + 105,62 MeV/c2. c4
E2 = 8,41 . 0.99+ 11151,36. 0.98
E2 = 8.32 + 10928,3
E2 = 10936,653 E= 104,5
PION
P = m.V (m pion’s relativity heap)
m= m
1- V2 / c2 = 141,8
E2 = 141,82 MeV/c .c2 + 1392 MeV/c2 .c4
E2 = 19906 +18934,5 = 38840;5 E= 197 MeV
NEUTRINO’S ENERGY
197 MeV – 104,5 MeV = 92,5 MeV